Python list内元素生成新的组合怎么写,pythonlist,比如l = [1,2,3


比如l = [1,2,3]
指定长度2,就会得到[1,2][2,3][1,3],不考虑顺序。

生成排列可以用product:

from itertools import productl = [1, 2, 3]print list(product(l, l))print list(product(l, repeat=4))

组合的话可以用combinations:

from itertools import combinationsprint list(combinations([1,2,3,4,5], 3))

下面是我以为没有combinations然后自己写的,没有itertools的python(2.6以下)可供参考。

import copydef combine(l, n):     answers = []    one = [0] * n     def next_c(li = 0, ni = 0):         if ni == n:            answers.append(copy.copy(one))            return        for lj in xrange(li, len(l)):            one[ni] = l[lj]            next_c(lj + 1, ni + 1)    next_c()    return answersprint combine([1, 2, 3, 4, 5], 3)

输出:

[[1, 2, 3], [1, 2, 4], [1, 2, 5], [1, 3, 4], [1, 3, 5], [1, 4, 5], [2, 3, 4], [2, 3, 5], [2, 4, 5], [3, 4, 5]]

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