Python代码, 仿照玩蛇网经典代码单例, 却出现了不是单例的的状态, 帮助看下源码，python源码,实际现象期望实现单例,

实际现象

期望实现单例, 保持某个属性全局唯一

预期现象

仿照经典实现代码, 却出现了不是单例的情况

我要做什么

实现scheduler全局唯一, 不派生过多的scheduler

重现步骤

拷贝代码

运行之

查看内存地址

相关代码

仿照经典实现

from apscheduler.schedulers.background import BackgroundSchedulerclass Borg(object):        __shared_state = {}    def __init__(self):        self.__dict__ = Borg.__shared_state        self.scheduler = BackgroundScheduler()                s1 = Borg().schedulers2 = Borg().schedulerprint s1, s2# <apscheduler.schedulers.background.BackgroundScheduler object at 0x02623DF0> # <apscheduler.schedulers.background.BackgroundScheduler object at 0x02D801D0>

我自己想的办法

from apscheduler.schedulers.background import BackgroundSchedulerclass Borg(object):    @classmethod    def get_scheduler(cls):        try:            cls_scheduler = cls.scheduler        except AttributeError as e:            cls.scheduler = BackgroundScheduler()            return cls.scheduler        else:            return cls_scheduler        bs1 = Borg.get_scheduler()bs2 = Borg.get_scheduler()bs3 = Borg.get_scheduler()print bs1, bs2, bs3# <apscheduler.schedulers.background.BackgroundScheduler object at 0x02752D70> # <apscheduler.schedulers.background.BackgroundScheduler object at 0x02752D70> # <apscheduler.schedulers.background.BackgroundScheduler object at 0x02752D70>

上下文环境

产品版本: Python 2.7 APScheduler最新

操作系统: Linux

Github链接, 经典实现: https://github.com/faif/pytho...

s1 = Borg().schedulers2 = Borg().scheduler

s1 = Borg()print(s1.scheduler)s2 = Borg()print(s1.scheduler)print(s2.scheduler)print(s1.scheduler is s2.scheduler)

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