Python分割字符串如实现最优雅，python分割字符串, 分割一个字符串时最简

像下面的那样，基本思路是直接长度除分数得到每份的长度，如果有余数的话前余数份长度各加1。avsplit1看上去比avsplit2要pythonic 一些，但是性能方面avsplit2好点。

Pythons = 'abcdefghijklmn'n = 5def avsplit1(s, n):    fn = len(s)//n    rn = len(s)%n    ar = [fn+1]*rn+ [fn]*(n-rn)    si = [i*(fn+1) if i<rn else (rn*(fn+1)+(i-rn)*fn) for i in xrange(n)]    sr = [s[si[i]:si[i]+ar[i]] for i in xrange(n)]    return srdef avsplit2(s, n):    fn = len(s)//n    rn = len(s)%n    sr = []    ix = 0    for i in xrange(n):        if i<rn:            sr.append(s[ix:ix+fn+1])            ix += fn+1        else:            sr.append(s[ix:ix+fn])            ix += fn    return srprint avsplit1(s,n)print avsplit2(s,n)

pythondef segmented(iterable):    def _seg(width):        it = iterable        while len(it) > width:            yield it[:width]            it = it[width:]        yield it    return _seg

python>>> s = 'asdfghji'>>> split_every = segmented(s)>>> print(list(split_every(2)))['as', 'df', 'gh', 'ji']>>> print(list(split_every(3)))['asd', 'fgh', 'ji']>>> print(s)asdfghji

    s = 'ABCDEFGHIJKLMNOPQRSTUVWXYZ'    n = 3    print([s[i:i+n] for i in xrange(0, len(s), n)])    #['ABC', 'DEF', 'GHI', 'JKL', 'MNO', 'PQR', 'STU', 'VWX', 'YZ']